x^3-4x+3/x

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Solution for x^3-4x+3/x equation:


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

x^3-(4*x)+3/x = 0

x^3-4*x+3/x = 0

1*x^3-4*x^1+3*x^-1 = 0

(1*x^4-4*x^2+3*x^0)/(x^1) = 0 // * x^2

x^1*(1*x^4-4*x^2+3*x^0) = 0

x^1

x^4-4*x^2+3 = 0

{ 1, -1, 3, -3 }

1

x = 1

x^4-4*x^2+3 = 0

1

x-1

x^3+x^2-3*x-3

x^4-4*x^2+3

x-1

x^3-x^4

x^3-4*x^2+3

x^2-x^3

3-3*x^2

3*x^2-3*x

3-3*x

3*x-3

0

x^3+x^2-3*x-3 = 0

{ 1, -1, 3, -3 }

1

x = 1

x^3+x^2-3*x-3 = -4

1

-1

x = -1

x^3+x^2-3*x-3 = 0

-1

x+1

x^2-3

x^3+x^2-3*x-3

x+1

-x^3-x^2

-3*x-3

3*x+3

0

x^2-3 = 0

DELTA = 0^2-(-3*1*4)

DELTA = 12

DELTA > 0

x = (12^(1/2)+0)/(1*2) or x = (0-12^(1/2))/(1*2)

x = 3^(1/2) or x = -3^(1/2)

x in { -3^(1/2), 3^(1/2), 1, -1}

x in { -3^(1/2), 3^(1/2), 1, -1 }

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